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BJP3 Self-Check 5.22: deMorgansExpressions

Author: Marty Stepp (on 2013/09/02)

Consider the following variable declarations. Write a new Boolean expression that is the negation of each of the following Boolean expressions. For the longer expressions, use De Morgan's laws rather than simply writing a ! at the beginning of each entire expression. (For Practice-It to accept your solution, your answers should be as similar as possible to the original expressions while changing the various operators between parts of the expression.)

(x > y) && (y > z)
(x == y) || (x <= z)
(x % 2 != 0) && b
(x / 2 == 13) || b || (z * 3 == 96)
(z < x) && (z > y || x >= y)

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