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sequenceSum

Language/Type: Java method basics println return
Author: Whitaker Brand (on 2010/12/28)

Write a method named sequenceSum that prints terms of the following mathematical sequence:

sequence

Your method should accept a real number as a parameter representing a limit, and should add and print terms of the sequence until the sum of terms meets or exceeds that limit. For example, if your method is passed 2.0, print terms until the sum of those terms is at >= 2.0. You should round your answer to 3 digits past the decimal point.

The following is the output from the call sequenceSum(2.0);

1 + 1/2 + 1/3 + 1/4 = 2.083

(Despite the fact that the terms keep getting smaller, the sequence can actually produce an arbitrarily large sum if enough terms are added.) If your method is passed a value less than 1.0, no output should be produced. You must match the output format shown exactly; note the spaces and pluses separating neighboring terms. Other sample calls:

call: sequenceSum(0.0); sequenceSum(1.0); sequenceSum(1.5);
output: 1 = 1.000 1 + 1/2 = 1.500
call: sequenceSum(2.7);
output: 1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 = 2.718
Type your solution here:


This is a method problem. Write a Java method as described. Do not write a complete program or class; just the method(s) above.

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