Write a method compressDuplicates that takes a
stack of integers as a parameter and that replaces each sequence of
duplicates with a pair of values representing a count of the number of
duplicates followed by the number. For example, suppose a variable called s
stores the following sequence of values:
bottom [2, 2, 2, 2, 2, -5, -5, 3, 3, 3, 3, 4, 4, 1, 0, 17, 17] top
and we make the following call:
compressDuplicates(s);
Then s should store the following values after the call:
bottom [5, 2, 2, -5, 4, 3, 2, 4, 1, 1, 1, 0, 2, 17] top
This new stack indicates that the original had 5 occurrences of 2 at the
bottom of the stack followed by 2 occurrences of -5 followed by 4
occurrences of 3, and so on. This process works best when there are many
duplicates in a row. For example, if the stack instead had stored:
bottom [10, 20, 10, 20, 10, 20] top
Then the resulting stack ends up being longer than the original:
bottom [1, 10, 1, 20, 1, 10, 1, 20, 1, 10, 1, 20] top
If the stack is empty, your method should not change it. You are to use one
queue as auxiliary storage to solve this problem. You may not use any other
auxiliary data structures to solve this problem, although you can have as
many simple variables as you like. You may not use recursion to solve this
problem and your solution must run in O(n) time. Use the Stack and Queue
interfaces and the ArrayStack and LinkedQueue implementations discussed in
lecture.