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countToBy

Language/Type: Java recursion recursive programming
Author: Whitaker Brand

Write a method countToBy that accepts integer parameters n and m and that produces output indicating how to count to n in increments of m separated by commas. For example, to count to 10 by 1 you'd say countToBy(10, 1); The following table shows several other calls and their expected output:

Call Meaning Output
countToBy(10,1); count to 10 by 1s 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
countToBy(25,4); count to 25 by 4s 1, 5, 9, 13, 17, 21, 25
countToBy(30,4); count to 30 by 4s 2, 6, 10, 14, 18, 22, 26, 30
countToBy(34,5); count to 34 by 5s 4, 9, 14, 19, 24, 29, 34
countToBy(3,6); count to 3 by 6s 3
countToBy(17,3); count to 17 by 3s 2, 5, 8, 11, 14, 17

Notice that the increment does not have to be 1, such as when counting to 25 by 4s. The count must always end at n, but notice that at will not always be possible to start counting at 1, as shown in the output when n is 30 and m is 4. But the first number should always be in the range of 1 to m inclusive. It is possible that only one number will be printed, as shown in the output when n is 3 and m is 6.

Your method should throw an IllegalArgumentException if either m or n is less than 1. Note that the output does not advance to the next line.

Type your solution here:


This is a method problem. Write a Java method as described. Do not write a complete program or class; just the method(s) above.

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